A little algebra help: Solve hp - 1 = q + kp + 6p for p

[xtrmk]

I'm not really strong in Algebra so I would appreciate it if anyone can help me:

1) Solve for p: hp - 1 = q + kp + 6p

Only thing I could do is move the 1 over and then divide by p? I bet im wrong, help is really appreciated thanks ..

2) Solve for x: [ 3(x+2)^-1 ] - [ 4/x ] = 0

I'm clueless

 

[stapel]

1) Get all the terms containing "p" on one side of the equation, with all the other terms on the other side. On the side with "p", factor the target variable out of all of the terms, so you get "p(some other stuff) = (the rest of the terms)". Then divide off (some other stuff) to get the target variable by itself.

2) A good first step would probably be to multiply through by the common denominator, x(x + 2), since this will get rid of both of the fractions. Then solve the resulting linear equations.

If you get stuck, please reply showing how far you have gotten. Thank you.

Eliz.

 

[xtrmk]

1) Get all the terms containing "p" on one side of the equation, with all the other terms on the other side. On the side with "p", factor the target variable out of all of the terms, so you get "p(some other stuff) = (the rest of the terms)". Then divide off (some other stuff) to get the target variable by itself.

2) A good first step would probably be to multiply through by the common denominator, x(x + 2), since this will get rid of both of the fractions. Then solve the resulting linear equations.

If you get stuck, please reply showing how far you have gotten. Thank you.

Eliz.

Is the answer for the first one p = (q+1) / (h-k-6) ?

2) Am i doing it right so far? I don't know what to do from here:

[ (3x) / (x(x+2) ] - [ 4(x+2) ] / [ (x(x+2) ] = 0

[ (3x) / (x(x+2) ] = [ 4(x+2) ] / [ (x(x+2) ]

Do I cross multiply from here? If so, do the x and (x+2) cancel each other out? Help is appreciated.

 

[stapel]

Is the answer for the first one p = (q+1) / (h-k-6) ?

That's what I get.

2) Am i doing it right so far? I don't know what to do from here:

[ (3x) / (x(x+2) ] - [ 4(x+2) ] / [ (x(x+2) ] = 0

Okay; converting to the common denominator is another way of doing this. Now add the common-denominator fractions, and recall that a fraction is zero only when the numerator is zero. Solve the resulting linear equation.

Eliz.

 

[Denis]

[ 3(x+2)^-1 ] - [ 4/x ] = 0

Another way of doing that one:

3 / (x+2) = 4 / x ; crisscross multiply:
4(x+2) = 3x
Can you finish it?

 

[xtrmk]

[ 3(x+2)^-1 ] - [ 4/x ] = 0

Another way of doing that one:

3 / (x+2) = 4 / x ; crisscross multiply:
4(x+2) = 3x
Can you finish it?

Oh wow thanks lol i got -8 doing it your way and -8 doing it the other way but when I checked it before it didn't work but now it does, how stupid of me.. thanks for the help.