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99% in room are men; also 3 women. how many men must leave...?
- Thread starter galois
- Start date
D
Deleted member 4993
Guest
[SIZE=-1]99% of the people in a room are men. How many men would have to leave the room in order for this percentage to decrease to 98%? It is known that the number of women in the room is 3.[/SIZE]
Please help.
1% of "what" number = 3
1% of "what" number = 3
I know that.There are 300 people in the room.But I don't know how to get the result.
set up a equation
assume x is the men to leave.
(number of men - x) / (total number of people - x) = 0.98
can you solve it for me please.
HallsofIvy
Elite Member
- Joined
- Jan 27, 2012
- Messages
- 7,763
If you are not taking an algebra course where did you get this problem? It won't do you any good for someone to do the problem for you. You have already determined that there were 300 people and 3 of them are women so the other 300- 3= 297 are men. If "x" men leave the room there will be 297- x men and 300- x people. The percentage that are men will be \(\displaystyle \frac{297- x}{300- x}= 0.97\). That is the equation JohnZ gave you. You can "get rid" of the fraction by multiplying both side by 300- x. What do you get when you do that?
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