9^(3x) = 27^(x+1) I dont even know where to begin

[kaynm]

9[sup:13w1inni]3x[/sup:13w1inni]=27[sup:13w1inni]x+1[/sup:13w1inni]

I dont even know where to begin

 

[Denis]

Re: HELP

9[sup:1xdooosd]3x[/sup:1xdooosd]=27[sup:1xdooosd]x+1[/sup:1xdooosd]
I dont even know where to begin

WHY do you not know where to begin? Missed math classes?
What grade are you in?

 

[stapel]

I dont even know where to begin

If the above is true, then it is highly unlikely that we would be able to assist. So I hope you are exaggerating. Please clarify:

Are you familiar at all with variables (the letters in the equation)? Have you solved equations of any sort? Are you familiar with powers (the raised bits are "exponents" or "powers")? If not, then I'm afraid you need much more help than we can here provide. If so, then please reply showing how you have applied that knowledge in beginning your solution attempt.

Thank you!

Eliz.

 

[Deleted member 4993]

9[sup:34ghrg4a]3x[/sup:34ghrg4a]=27[sup:34ghrg4a]x+1[/sup:34ghrg4a]

I dont even know where to begin

Hint:

\(\displaystyle 9 \, = 3^2\)

and

\(\displaystyle 27 \, = 3^3\)

and

\(\displaystyle (a^m)^n = a^{m\cdot n}\)