Assume that he attends randomly with probability 0.55
and that each decision is independent of previous attendance, so that the
process can be viewed as a Bernoulli process.
What is the probability that he attends at least 8 of 10 classes
given that he attends at least 2 but not all 10 classes?
I thought it would be easier to calculate the probability for 0, 1, and 10 and then add those answers together and subtract it from 1.
I tried this:
(.55^0)*(.45^10)*C(10,0)=3.41*10^-4
(.55^1)*(.45^9)*C(10,1)=.0042
(.55^10)*(.45^0)*C(10,10)=.0025329516
I added those answers together and subtracted it from 1 and got .993- This seems right to me, but the homework says it's wrong
and that each decision is independent of previous attendance, so that the
process can be viewed as a Bernoulli process.
What is the probability that he attends at least 8 of 10 classes
given that he attends at least 2 but not all 10 classes?
I thought it would be easier to calculate the probability for 0, 1, and 10 and then add those answers together and subtract it from 1.
I tried this:
(.55^0)*(.45^10)*C(10,0)=3.41*10^-4
(.55^1)*(.45^9)*C(10,1)=.0042
(.55^10)*(.45^0)*C(10,10)=.0025329516
I added those answers together and subtracted it from 1 and got .993- This seems right to me, but the homework says it's wrong