5 probs I've done can u chk for me please

[LisaM2010]

1. 1/2(6x-8)=1/4(16x-12) I used 5 for 1/2 and 25 for 1/4 4. 10r+8=28
30x-40=500x-290 R=3 4/8 my answer
-30 -30
x-40=460x-290 5. 6-(x-2)=-6+5(x+10)
+40 +40 6-x-2=-6+5x+50
x=460x-330 4-x = 56+5x
divide 460/330= 1 130/330 x = 52+5x my answer
x=1 130/330 my answer

2. 1/2x > 1/6x

Im not for sure how to work it but I believe it is true...

3. 3(x+2)-(3x+6)=0

3x+6-3x+6+0
-6 -6
3x-3x=0
0 my answer

 

[Denis]

1. 1/2(6x-8)=1/4(16x-12) I used 5 for 1/2 and 25 for 1/4 4. 10r+8=28
30x-40=500x-290 R=3 4/8 my answer
-30 -30
x-40=460x-290 5. 6-(x-2)=-6+5(x+10)
+40 +40 6-x-2=-6+5x+50
x=460x-330 4-x = 56+5x
divide 460/330= 1 130/330 x = 52+5x my answer
x=1 130/330 my answer

WHY are you expecting us to be able to "decipher" that?
There seems to be 3 different problems in that mess!
You were asked to post ONLY ONE problem per thread: is that too much to ask?

 

[mmm4444bot]

I used 5 for 1/2 and 25 for 1/4

Oh no, Lisa!

You need to realize that 1/2 is not the same number as 5.

Likewise, 25 does not equal 1/4.

You must be thinking of decimal forms for the fractions 1/2 and 1/4.

1/2 = 0.5

1/4 = 0.25

I suggest that you learn how to do arithmetic with fractions, and leave the decimal versions and your calculator alone.

Otherwise, you're going to be miserable throughout your algebra classes and beyond.

Here is a site for learning how to do arithmetic with fractions (i.e., rational numbers like 1/2 and 1/4).

Now, I am trying to decipher the rest of your garbled post …

 

[mmm4444bot]

4. 10r + 8 = 28

R = 3 4/8 my answer

Nope.

By the way, the symbols R and r do not mean the same thing. They are not interchangable. Always stick with the symbol you're given.

10r + 8 = 28

Here are the two steps. See if you can do them.

(1) Subtract 8 from both sides

(2) Divide both sides by 10



5. 6-(x-2)=-6+5(x+10)

6-x-2=-6+5x+50 ? Be careful with signs when subtracting.

6 - (-2) is not 6 - 2.

It is 6 + 2.

Please correct this mistake, and continue.



2. 1/2x > 1/6x

Im not for sure how to work it but I believe it is true...

This inequality is not true for all values of x; it is only true for some values.

You need to find the set of values for x that make it true.

Can you multiply both sides of this inequality by 6 ? That will clear the fractions.

Next, subtract x from both sides.

Finish by dividing both sides by 2.

3. 3(x+2)-(3x+6)=0

3x+6-3x+6+0

You missed a sign, again.

- (3x + 6) means that each term inside the paretheses is being subtracted.

After this subtraction, you have:

3x + 6 - 3x - 6 = 0

The result is 0 = 0, and this result means that the given equation is true for all values of x.

This web site strips out repeated spaces, so you cannot position stuff on the screen using word spaces.

In the future, please post each exercise in a separate thread.

Thank you for showing your work.

 

[LisaM2010]

Thank You I will ty again...