(3x+4)arcsin[x], arcsin(y)+3y^2/2+4y-int(3y^2/2+4y)/sqrt(1-y

[kpx001]

i know i need to use parts and trig
x = sintheta.
i get up to arcsin(y)+3y^2/2 +4y - intergral (3y^2/2 + 4y ) /sqroot(1-y^2) , but it gets super messy.

3sin^2@/2 +4sin@ is as far as i get in the intergral

This problem is for understanding purpose.

 

[stapel]

i know i need to use parts and trig

On what are you "needing to use parts and trig"? Does "parts" mean "integration by parts"?

i get up to arcsin(y)+3y^2/2 +4y - intergral (3y^2/2 + 4y ) /sqroot(1-y^2)...

'
From whence did you "get up to" this? What was the original question?

Please be complete. Thank you!

Eliz.

 

[royhaas]

To integrate \(\displaystyle (3x+4)sin^{-1}x\), split it up. The arcsine part works well by parts. Use the trig substitution in the first integral, followed by parts and resubstitution.