i have a simitanious equation 4x+2y=26 3x+3y=20. Is there a solution or is it a misprint????
S swimbad New member Joined Oct 12, 2005 Messages 1 Oct 12, 2005 #1 i have a simitanious equation 4x+2y=26 3x+3y=20. Is there a solution or is it a misprint????
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Oct 12, 2005 #2 Is what a misprint? The system of equations, or the solution in the back of the book? Thank you. Eliz.
Is what a misprint? The system of equations, or the solution in the back of the book? Thank you. Eliz.
T ting Junior Member Joined Sep 18, 2005 Messages 87 Oct 12, 2005 #3 There's a bunch of ways. Here's one. 4x+2y=26 [1] 3x+3y=20 [2] Divide equation [1] by 2 2x + y = 13 [3] Now multiply [3] by 3 6x + 3y = 39 [4] Subtract [2] from [4] 6x + 3y = 39 3x + 3y=20 3x = 19 x = 19/3 Substitute into 2 and solve for y. 19 + 3y = 20 3y = 1 y = 1/3
There's a bunch of ways. Here's one. 4x+2y=26 [1] 3x+3y=20 [2] Divide equation [1] by 2 2x + y = 13 [3] Now multiply [3] by 3 6x + 3y = 39 [4] Subtract [2] from [4] 6x + 3y = 39 3x + 3y=20 3x = 19 x = 19/3 Substitute into 2 and solve for y. 19 + 3y = 20 3y = 1 y = 1/3
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Oct 12, 2005 #4 Hello, swimbad! (1) 4x + 2y = 26 (2) 3x + 3y = 20 Is there a solution or is it a misprint???? Click to expand... Sorry, but why wouldn't there be a solution? Divide (1) by 2: . 2x + y .= .13 Divide (2) by 3: . . x + y .= .20/3 Subtract: .x .= .13 - 20/3 .= .19/3 . . . . .Then: .y .= .1/3
Hello, swimbad! (1) 4x + 2y = 26 (2) 3x + 3y = 20 Is there a solution or is it a misprint???? Click to expand... Sorry, but why wouldn't there be a solution? Divide (1) by 2: . 2x + y .= .13 Divide (2) by 3: . . x + y .= .20/3 Subtract: .x .= .13 - 20/3 .= .19/3 . . . . .Then: .y .= .1/3
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Oct 12, 2005 #5 Is this an acceptable shortcut: 4x+2y=26 [1] 3x+3y=20 [2] change [2] to: 4x + 3y = 20 + x subtract [1] from that: y = x - 6
Is this an acceptable shortcut: 4x+2y=26 [1] 3x+3y=20 [2] change [2] to: 4x + 3y = 20 + x subtract [1] from that: y = x - 6