If K=2^31* 3^19, how many +ve divisors of K^2 are less than K But do not divide K?
S sujoy Junior Member Joined Apr 30, 2005 Messages 110 Oct 7, 2005 #1 If K=2^31* 3^19, how many +ve divisors of K^2 are less than K But do not divide K?
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Oct 7, 2005 #2 boy oh boy oh boy oh boy....... sujoy, do you even know what your question is or means? What are you studying? What grade are you in? Why do you not show what you tried?
boy oh boy oh boy oh boy....... sujoy, do you even know what your question is or means? What are you studying? What grade are you in? Why do you not show what you tried?
S sujoy Junior Member Joined Apr 30, 2005 Messages 110 Oct 7, 2005 #3 no. of factors in K^2 is 63*39.If K be excluded , we getpairs as [x,K^2/x], also one here is less than K
no. of factors in K^2 is 63*39.If K be excluded , we getpairs as [x,K^2/x], also one here is less than K
