300e^-.076t when t = 15

wilc0919

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Oct 13, 2006
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I got 300e^-.076(15) = 300e^-1.14

then I put -1.14 ln 300 ln e = -1.14 * 5.7037 = -6.5022 IS THIS RIGHT?
 
wilc0919 said:
I got 300e^-.076(15) = 300e^-1.14
"I got" implies that this is a later stage in your computations. That is, that the above is not the actual exercise. Without having the actual exercise, it is difficult to evaluate correctness.

Is the exercise in the subject line? (Subject lines frequently do not contain relevant content, so please forgive me if this assumption is incorrect.) If so, then is "t" in the exponent, or not? That is, is the expression "300 e^(-0.076 t)" or "(300 e^(-0.076)) t"?

wilc0919 said:
then I put -1.14 ln 300 ln e = -1.14 * 5.7037 = -6.5022 IS THIS RIGHT?
Where are the natural logs coming from...?

Please reply with clarification. Thank you.

Eliz.
 
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