3.5 Transformation of a function exercises

I

Illvoices

Junior Member
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Jan 13, 2017
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116
hi could anyone tell me how to graph the following:
f(x)=x2
f(x)=x2-1
f(x)=x​2+1
 
One of the easiest ways to graph a simple "well-behaved" function is to make a T-chart. Essentially, you just pick a few points and plot them to get a general feel for how the graph behaves, then "connect the dots." Start with x2. Then when you're making your T-charts, pay close attention to your y values of x2-1 and x2+1 respectively. Particularly, compare them to the "original" x2. How do the y-values for the same x-values differ? What pattern are you noticing? Do you predict this pattern will extend to all values? Why or why not?
 
i know there is a pattern to the problem, i just wanted to know how to plot the point for x2 in chart?
 
Uh... I'm sorry, but I don't understand what, exactly, it is that's giving you troubles. Making a T-chart is literally just writing down the outputs (f(x) aka y) for some given inputs (x). You're given that "y, as a function of x, is equal to x squared." Are you saying you're having trouble squaring a number?
 
i just need help graphing x2 in the chart because i dont know where it goes.
 
Illvoices said:
i just need help graphing x2 in the chart because i dont know where it goes.
Click to expand...

Consider the values eg x= -3, -2, -1, 0, 1, 2, 3 for starters.

Take the first one. If x=-3, f(-3) = (-3)^2 = 9......So (-3, 9) is a point on the graph. Plot it.

Now do the same for x=-2, x=-1, etc.

Then join the dots (with a nice curve).
 
Harry_the_cat said:
Consider the values eg x= -3, -2, -1, 0, 1, 2, 3 for starters.

Take the first one. If x=-3, f(-3) = (-3)^2 = 9......So (-3, 9) is a point on the graph. Plot it.

Now do the same for x=-2, x=-1, etc.

Then join the dots (with a nice curve).
Click to expand...
ty
 
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