(3/5)^2 + 8/35 divided by 24/7

[kmerr98277]

(3/5)^2 + 8/35 divided by 24/7
Do I first solve (3/5)^2 then find a common denominator with 8/35 and add them then divide that by 4/7?
or...
first find a CD with all three
Thanks.

 

[stapel]

(3/5)^2 + 8/35 divided by 24/7
Do I first solve (3/5)^2 then find a common denominator with 8/35 and add them then divide that by 4/7?
or...
first find a CD with all three

I will guess that "CD" is your personal nickname for "least common denominator".

How do you propose to find a common denominator before simplifying the exponential expression?

Try simplifying first. Then do the addition. Then flip-n-multiply.

 

[lookagain]

(3/5)^2 + 8/35 divided by 24/7
Do I first solve (3/5)^2 then find a common denominator with 8/35 and add them then divide that by 4/7?
or...
first find a CD with all three
Thanks.

kmerr98277, does the original form of the problem use the division sign as I typed here?


\(\displaystyle \bigg(\dfrac{3}{5}\bigg)^2 \ + \ \dfrac{8}{35} \ \div \ \dfrac{24}{7}\)

 

[Quaid]

(3/5)^2 + 8/35 divided by 24/7

Do I first [evaluate] (3/5)^2 then find a common denominator with 8/35 and add them then divide that by [24/7]?

Hi kmerr

Yes, those steps are correct, if the given exercise is like this:

\(\displaystyle \dfrac{(3/5)^{2} + 8/35}{24/7}\)


What answer do you get? :cool:


PS: Typos corrected above in red (I'm guessing that your 4/7 is supposed to be 24/7, and not the other way around).

Plus, here's how to text the blue expression using proper grouping symbols:

[(3/5)^2 + 8/35]/[24/7]