(2a^-4b^2)^4 (ab^-2)^5

chesterdg123

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Jun 9, 2008
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21
Just need a check on this problem!

Thanks!


=(16a^-16b^8)(a^5 b^-10)

=16 a^-16+5 b^8+(-10)

=16 a^-11 b^-2

=16/a^11 b^2
 
chesterdg123 said:
=(16a^-16b^8)(a^5 b^-10)
=16 a^-16+5 b^8+(-10)
=16 a^-11 b^-2
=16/a^11 b^2
Correct, but brackets required: 16/(a^11 b^2)
 
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