25 - 4u/3 = 5u + 12/4 + 6

[dionnewatkins]

25 - 4u/3 = 5u + 12/4 + 6

HELP! It's been a long time! Can someone please walk me through it?

 

[JoeTrumpet]

25 - 4u/3 = 5u + 12/4 + 6 ----- simplify 12/4 to 3
25 - 4u/3 = 5u + 3 + 6 ----- add it to the 6 to get 9
25 - 4u/3 = 5u + 9 ----- get rid of the fraction by multiplying the whole equation by 3
75 - 4u = 15u + 27 ----- add 4u to both sides and subtract 27 from both to combine variables
19u = 48 ----- divide by 19 on both sides
u = 48/19 ----- this will be your final answer, unless you want it in decimal in which case you just divide it

hope that helps!

 

[Denis]

Where were you stuck with that, Dionne ?

 

[dionnewatkins]

The problem was:

the entire 25-4u was over 3 = 5u+12 over 4 + 6.

I didn't know how exactly to write it. I guess maybe like the following would be better in the future.

25-4u = 5u+12 + 6
3 4

bue the 4 is under the 5u+12

 

[Denis]

I see...makes a huge difference! Next time, post like this:

(25 - 4u) / 3 = (5u + 12) / 4 + 6

Multiply each term by 12 (12 is the lcd):
4(25 - 4u) = 3(5u + 12) + 72

Complete the multiplications:
100 - 16u = 15u + 36 + 72

15u + 16u = 100 - 36 - 72
31u = -8
u = -8/31

If you didn't follow what I did, you need to talk to your teacher...

 

[stapel]

The problem was...

But what were the instructions? We've been guessing that you were supposed to solve. Was this correct?

Thank you.

Eliz.

 

[dionnewatkins]

Yes, I was supposed to solve. My problem was that when I reduced the 12 to a 4 to get rid of the fraction...I applied the 4 to the 6...not 12.

Thank you guys. I will definitely pay more attention to that in the future!!! I really appreciate your help!