**2 Column Proof Help??**

careness

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Nov 26, 2008
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I must complete the reason column where it says [1], [2], and [3].
If you could help please do. Thanks.
 

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RS=RU given
angle SRT = angle URT given
RT is common to both triangles

triangle SRT = triangle URT.............. side angle side

Arthur
 
I respectfully disagree with the answers given in the previous post.
The reason for [1] is "Perpendicular lines form right angles." This is usually a theorem. It is NOT the definition of perpendicular lines.
The reason for [2] is "If two sides of a triangle are congruent, then the angles opposite those sides are congruent." This is also a theorem, sometimes called the Isosceles Triangle Theorem.
The reason for [3] is "Reflexive Property of Congurence."
 
fasteddie65 said:
I respectfully disagree with the answers given in the previous post.
The reason for [1] is "Perpendicular lines form right angles." This is usually a theorem. It is NOT the definition of perpendicular lines.
The reason for [2] is "If two sides of a triangle are congruent, then the angles opposite those sides are congruent." This is also a theorem, sometimes called the Isosceles Triangle Theorem.
The reason for [3] is "Reflexive Property of Congurence."
thanks, your answer made sense.
 
Hello, careness!

Who wrote this problem?
It is very badly written and its purpose escapes me.


Given:   (1)RTSU(2)SRT=U ⁣RT(3)RS=RU(4)T is midpt of SU\displaystyle \text{Given: }\;\begin{array}{cc}(1) & \overline{RT} \perp \overline{SU} \\ (2) & \angle SRT = \angle U\!RT \\ (3) & \overline{RS} = \overline{RU} \\ (4) & T\text{ is midpt of }\overline{SU} \end{array}

Prove: ΔRTSΔRTU\displaystyle \text{Prove: }\:\Delta RTS \,\cong\,\Delta RTU

Code:
              R
              *
            * | *
          *   |   *
        *     |     *
    S *   *   *   *   * U
              T

The problem is severely overstated.
. . In an isosceles triangle, the bisector of the vertex angle
. . is always perpendicular to the base and always bisects the base.

So there are several possible proofs **
. . and they picked one which asks rather pointless questions.

Line 2 asks: Do you know how to say "Perpendicular lines form right angles" ?

Line 5 asks: Do you know that "Base angles of an isosceles triangle are equal" ?

Line 9 asks: How do you say "A thing is equal to itself" ?

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

**

Another proof:\displaystyle \text{Another proof:}

.StatementReason(1)ST=TUdef. of midpoint(2)RS=RUGiven(3)RT=RTLine 9(4)ΔRTSΔRTUs.s.s\displaystyle \begin{array}{cccc} & \text{Statement} && \text{Reason} \\ \hline (1) & ST = TU & & \text{def. of midpoint} \\ (2) & RS = RU & & \text{Given} \\ (3) & RT = RT && \text{Line 9} \\ (4) & \Delta RTS \cong \Delta RTU && \text{s.s.s} \end{array}



And another:\displaystyle \text{And another:}

. . StatementReason(1)RS=RUGiven(2)SRT=URTGiven(3)RT=RTLine 9(4)ΔRTSΔRTUs.a.s\displaystyle \begin{array}{cccc} & \text{Statement} && \text{Reason} \\ \hline (1) & RS = RU && \text{Given} \\ (2) & \angle SRT = \angle URT && \text{Given} \\ (3) & RT = RT && \text{Line 9} \\ (4) & \Delta RTS \cong \Delta RTU && \text{s.a.s} \end{array}



And yet another:\displaystyle \text{And yet another:}

. . StatementReason(1)SRT=URTGiven(2)RS=RUGiven(3)S=ULine 5(4)ΔRTSΔRTUa.s.a\displaystyle \begin{array}{cccc} & \text{Statement} && \text{Reason} \\ \hline (1) & \angle SRT = \angle URT && \text{Given} \\ (2) & RS = RU & & \text{Given} \\ (3) & \angle S = \angle U & & \text{Line 5} \\ (4) & \Delta RTS \cong \Delta RTU && a.s.a \end{array}

 
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