(2^5a^9b^5)(2a^-4b^3)/2^3a^6

[chesterdg123]

Hi, I just need to check my answer.

Thanks!


=(32a^9b^5)(2a^-4b^3)/2^3a^6

=(32*2)a^9-(-4) b^5+3/8a^6

=64a^5b^8/8a^6

=8a^5b^8/a^6

=8a^-1b^8

=8b^8\a

 

[jonboy]

=(32*2)a^9-(-4) b^5+3/8a^6

you're multiplying like bases, so you ADD the exponents.

thus you should have: \(\displaystyle a^{9 - 4} = a^5\)

but on the next line you got the right answer. probably just an absent minded mistake.

other than that, the mechanics and setup you done was good. *clap* *clap*

what a great showing!

 

[chesterdg123]

Thanks!

 

[Denis]

(2^5 a^9 b^5)(2 a^-4 b^3) / (2^3 a^6)

save yourself lots of typing by combining powers right away:

2^(5+1) a^(9-4) b^(5+3) / (2^3 a^6)
= 2^6 a^5 b^8 / (2^3 a^6) .....