125^1/3, 16^ -3/2, (9x^4y^2)^1/2, (27x^3)^ -1/3, etc.

Mahealy87

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Dec 12, 2007
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Simplify as much as possible making all exponents positive. Assume all variables represent positive numbers.

*I missed this day of class and I have my math final on Thursday!! Can someone please help me figure out how this is done?

125^1/3

16^ -3/2

x^3/5 * x^1/2

(9x^4y^2)^1/2

(27x^3)^ -1/3


Thanks!! :D
 
Re: 125^1/3

These should help:

\(\displaystyle a^{-n}= \frac{1}{a^{n}}\)

\(\displaystyle a^{\frac{m}{n}} = (\sqrt[n]{a})^{m} = \sqrt[n]{a^{m}}\)

\(\displaystyle a^{n} \cdot a^{m} = a^{m+n} \quad \mbox{Note that they have to have the same bases}\)

\(\displaystyle (a^{n}b^{m})^{z} = a^{z\cdot n} \cdot b^{z \cdot m}\)
 
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