[11th Grade Algebra] Need someone to verify if my answer is correct

[EnjoyablyC]

Hey guys, I just got finished with this problem and it was no answers anywhere, so I was wondering if someone could do a quick check on whether or not I got it correctly.

Here it is:

[32 b^(5/2) c^(-1/2)]^2/5 × [8^(2)b^(3)c^(-3/5)]^-1/3


After I factorize everything, and apply the exponents, I'm left with

2^(2) b c^(-2/10) × 2^(-2) b^(-1) c^(3/15)

Then I do

2^(2)× 2^(-2) = 2^0 = 1

b × b^(-1) = b^0 = 1

c^(-2/10) × c^(3/15) = c^-6/30 c^6/30 = c^0 = 1

1=1=1=3

The answer is 3? Am I correct or wrong in this assumption?

 

[DrPhil]

Hey guys, I just got finished with this problem and it was no answers anywhere, so I was wondering if someone could do a quick check on whether or not I got it correctly.

Here it is:

[32 b^(5/2) c^(-1/2)]^2/5 × [8^(2)b^(3)c^(-3/5)]^-1/3


After I factorize everything, and apply the exponents, I'm left with

2^(2) b c^(-2/10) × 2^(-2) b^(-1) c^(3/15)

Then I do

2^(2)× 2^(-2) = 2^0 = 1

b × b^(-1) = b^0 = 1

c^(-2/10) × c^(3/15) = c^-6/30 c^6/30 = c^0 = 1

1=1=1=3 NO - these are multiplicative factors, not additive terms

The answer is 3? Am I correct or wrong in this assumption?

Not correct.
1 × 1 × 1 = 1