Can someone explain to me how exactly this demonstration works?
[math]\frac{A^n}{A^m} = A^{n-m}[/math]
Demonstration:
Note that [math]A^m \cdot A^{n-m} = A^{m+(n-m)} = A^m[/math]
and since then[math]A \neq 0[/math] passing [math]A^m[/math] dividing the other side of the equality we find that [math]\frac{A^n}{A^m} = A^{n-m}[/math]
[math]\frac{A^n}{A^m} = A^{n-m}[/math]
Demonstration:
Note that [math]A^m \cdot A^{n-m} = A^{m+(n-m)} = A^m[/math]
and since then[math]A \neq 0[/math] passing [math]A^m[/math] dividing the other side of the equality we find that [math]\frac{A^n}{A^m} = A^{n-m}[/math]