by Wally » Thu Jul 29, 2010 7:05 am
To find the equation of a line, you need either two points that are on the line, or you need one point and the gradient (slope). In this problem, you will use one point and the gradient. You can get the point by solving the two equations (3y+x=3 and 4y+3x=5) in order to find what point is on both lines. You can get the gradient from the fact that the x-intercept of the line is twice its y-intercept. Draw a picture to help with this.
Now that you have the equation of the line, you want to know if the line is perpendicular with either line 3y+x=3 or line 4y+3x=5. The trick to know is the following. If two lines are parallel, then they have the same gradient. If two lines are perpendicular, then there gradients are negative reciprocals of each other. For example, if the gradient of a line is 3, then a line perpendicular to that line has a gradient of - 1/3. Draw another picture of this to see why.