Natasha13100
New member
- Joined
- Aug 30, 2014
- Messages
- 2
I am trying to prove n<10^n. Can I get some help?
So far:
for n=1, n<10^n because 1<10.
assume for n=k, k<10^k so n<10^n
therefore, k+1<10^k+1 (if a<b, a+c<b+c for any c)
this is where I'm stuck. Here is my guess:
for any positive integer k, 10^k will be a positive integer.
therefore, 10^(k+1)=10(10^k)>(10^k)+1.
thus, 10^(k+1)>k+1 (if a<b and b <c, a<c)
Only the last part has been proven so far so I don't think I'm doing this correctly.
So far:
for n=1, n<10^n because 1<10.
assume for n=k, k<10^k so n<10^n
therefore, k+1<10^k+1 (if a<b, a+c<b+c for any c)
this is where I'm stuck. Here is my guess:
for any positive integer k, 10^k will be a positive integer.
therefore, 10^(k+1)=10(10^k)>(10^k)+1.
thus, 10^(k+1)>k+1 (if a<b and b <c, a<c)
Only the last part has been proven so far so I don't think I'm doing this correctly.