I don't have an efficient solution in mind, perhaps there is a better one. We have a seven-digit integer abcdegf such that a+b+c+d+e+f+g = 19. The restrictions are: 1<a<=9, and each of b through g may be any of 0 through 9 subject to the constraint.
When a=1, we find b+...+f=18. Count the number of all "valid" unordered 6-partitions of 18 with allowing 0.
In other words we need to find "the number of ways to put 18 objects into 6 labeled boxes, with the restriction that each box contains a maximum of 9 objects". This in of itself looks very messy, and you will have to sum 9 such values.
Let N(n,k) be "the number of ways to distribute n indistinguishable objects among k distinguishable boxes such that each box has at most 9 objects".
Then your solution is \(\displaystyle \sum_{a=1}^9 N(19-a,6)\)
I haven't the slightest idea what a formula for what N(n,k) might look like, hopefully something like that has been covered in you class. However your answer is 111,573, certainly not 18 choose 6.